Question

If sin 0+ cos 0 = √3, then prove that tan 0 + cot 0 = 1​

Answer 1

$\bf\large\underline\pink{Solution:-}$

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Step by step Explanation :-

S.B.S

(Sin0 + Cos0)^2 = 3^2

Sin^2-0 + Cos^2-0 + 2sin0cos0 = 9

2sin0cos0 = 3-1 = 2

Sin0cos0 = 2/2 = 1

NOW,

tan0 + cot 0

= Sin0/cos0 + cos0/sin0

= Sin^2-0 + cos^2-0/ sin0cos0

= 1/1 = 1.

Answer 2

$\bf\large\underline\blue{Answer:-}$

(Sin0 + Cos0)^2 = 3^2

Sin^2-0 + Cos^2-0 + 2sin0cos0 = 9

2sin0cos0 = 3-1 = 2

Sin0cos0 = 2/2 = 1

NOW,

tan0 + cot 0

= Sin0/cos0 + cos0/sin0

= Sin^2-0 + cos^2-0/ sin0cos0

= 1/1 = 1.

Thank me later.