Question

If sin 0 + cos 0 - 3, then prove that tan 0 + cot 0 = 1

Answer 1

Answer:It's very easy just follow me.

Step-by-step explanation:

(Sin0 + Cos0)^2 = 3^2

Sin^2-0 + Cos^2-0 + 2sin0cos0 = 9

2sin0cos0 = 3-1 = 2

Sin0cos0 = 2/2 = 1

NOW,

tan0 + cot 0

= Sin0/cos0 + cos0/sin0

= Sin^2-0 + cos^2-0/ sin0cos0

= 1/1 = 1.

Thank me later.

Answer 2

Answer:

sin 0 + cos 0 = 3

Step-by-step explanation:

on squaring both side

sin² 0 + cos² 0 +2sin0.cos0 = 9

2 sin0.cos0 = 8

sin0.cos0 = 4

tan0 + cot0

sin0/cos0 + cos0/sin0

sin²0 + cos²0/ sin0.cos0

1/4 is the answer

pls check the Q and tell whether it is sin0 + cos0 = 3 or not