If sin 0 + cos 0 =y, and cos - sin 6 = x, then x 2 + y 2 is equal to
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Step-by-step explanation:
sinθ+cosθ=x
⇒sin
2
θ+cos
2
θ+2sinθcosθ=x
⇒1+2sinθcosθ=x
⇒sinθcosθ=(x−
2
1
)
sin
6
θ+cos
6
θ=(sin
2
θ)
3
+(cos
2
θ)
3
=(sin
2
θ+cos
2
θ)(sin
4
θ+cos
4
θ−sin
2
θcos
2
θ)
=((sin
2
θ+cos
2
θ)
2
−2sin
2
θcos
2
θ−sin
2
θcos
2
θ)=1−3sin
2
θcos
2
θ
=1−
4
3(x−1)
2
=
4
4−3(x−1)
2
.
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