Question

If sin 0 + cos = root 2, find value of sin -cos .

plss fassssstttttttt​

Answer 1

Answer:

[tex][/tex]

• Force is push or pull acting on a body which tends to change its state of rest or of motion.
• It is denoted by "F".

Answer 2

Answer:

0

Step-by-step explanation:

By squaring we get,

${( \sin(x) + \cos(x)) }^{2} = { \sqrt{2} }^{2}$

${ \sin(x) }^{2} + 2 \sin(x) \cos(x) + { \cos(x) }^{2} = 2$

$1 + 2 \sin(x) \cos(x) = 2$

$\sin(x) \cos(x) = \frac{1}{2}$

Now,

${( \sin(x) - \cos(x)) }^{2} = { \sin(x) }^{2} - 2 \sin(x) \cos(x) + { \cos(x) }^{2}$

${ (\sin(x) - \cos(x) ) }^{2} = 1 - 2 \times \frac{1}{2} = 0$

so,

$\sin(x) - \cos(x) = 0$