if sin 0 + coso 0/sin0 -coso 0 =3/5 , then find the value of 7tan 0+2 / 2tan 0 + 7
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Answer:
the value of 7tan 0+2 / 2tan 0 + 7 = -1
Explanation:
sin θ+ cosθ /sinθ -cosθ =3/5 ,
sin θ+ cosθ. 3
---------------- = ----
sin θ - cosθ. 5
Dividing. both Numerator & denominator by cosθ
(sin θ+ cosθ)/ cos θ. 3
--------------------------- = ----
(sin θ - cosθ.) / cosθ. 5
we get
( tan θ + 1 ). 3
----------------. = -----
( tan θ - 1 ). 5
cross multiplying
5 tan θ + 5 . = 3 tan θ - 3
5 tan θ - 3 tan θ = 3 - 5
2 tan θ = -2
tan θ = -1
7tan θ +2 7(-1) + 2. -5
------------. = ------------. = -----. = -1
2tan θ + 7. 2(-1) +7. 5
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