If sinθ=1/2 find 3cosθ -4cos³θ?
Answers
Answered by
11
Answer
Given sinθ=
2
1
⟹θ=
6
π
LHS
=3cosθ−4cos
3
θ=3cos
6
π
−4cos
3
6
π
=
2
3
3
−4(
2
3
)
3
=
2
3
3
−4×
8
3
3
=
2
3
3
−
2
3
3
=0
=RHS
Answered by
2
Answer:
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Step-by-step explanation:
Given sinθ=21
⟹θ=6π
LHS
=3cosθ−4cos3θ=3cos6π−4cos36π=233−4(23)3=233−4×833=233−233=0
=RHS
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