Math, asked by adityaraj200528, 1 month ago

If sinθ=1/2 find 3cosθ -4cos³θ?​

Answers

Answered by subhj7prime280917
11

Answer

Given sinθ=

2

1

⟹θ=

6

π

LHS

=3cosθ−4cos

3

θ=3cos

6

π

−4cos

3

6

π

=

2

3

3

−4(

2

3

)

3

=

2

3

3

−4×

8

3

3

=

2

3

3

2

3

3

=0

=RHS

Answered by Alijamee
2

Answer:

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Step-by-step explanation:

Given sinθ=21

⟹θ=6π

LHS

=3cosθ−4cos3θ=3cos6π−4cos36π=233−4(23)3=233−4×833=233−233=0

=RHS

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