If sin = 1/2 , find the value of 2sec A / 1 + tan^2 A.
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Answered by
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sinA = 1/2
∴A = 30
2secA / 1+tan²A
⇒2/cosA / 1/cos²A
⇒2 cosA
⇒2 cos30
∴2 * √3/2 = √3
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∴A = 30
2secA / 1+tan²A
⇒2/cosA / 1/cos²A
⇒2 cosA
⇒2 cos30
∴2 * √3/2 = √3
cheers and mark as brainliest!!!
Answered by
1
Answer:
Hi
√3
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