Math, asked by vivek9948, 1 year ago

if sin∅=1/2. find the value of 3cot²∅+2tan∅-2cos²∅​

Answers

Answered by Anonymous
1

Step-by-step explanation:

Here ,

sin theta = 1/2

so , theta = 30°

now,

from question

3 (\cot^{2} 30)  + 2( \tan(30) ) - 2( \cos^{2} 30)  \\  \\  = 3( \sqrt{3})^{2}  + 2( \frac{1}{ \sqrt{3} }) - 2( \frac{ \sqrt{3} }{2}  )^{2}  \\  \\  = 3(3) +  \frac{2}{3}  -  \frac{3}{2} \\  \\  = 9 +  \frac{2}{3}  -  \frac{3}{2}  \\  \\   =  \frac{54 + 4 - 9}{6}  \\  =  \frac{49}{6}  \\

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