. If sin = 1/2, then show that 3cos - 4cos
3 = 0.
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Answer:
Given sinθ=
2
1
⟹θ=
6
π
LHS
=3cosθ−4cos
3
θ=3cos
6
π
−4cos
3
6
π
=
2
3
3
−4(
2
3
)
3
=
2
3
3
−4×
8
3
3
=
2
3
3
−
2
3
3
=
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