Question

If sin-1(2a/1+a2) + cos-1(1−a2/1+a2) = tan-1(2x/1−x2) where a, x ∈ |0, 1| then the value of x is

Answer 1

Answer:

If sin-1 (2a/1+a2) + cos-1(1-a2/1+a2) = tan-1(2x/1-x2),where a, x ∈ [0,1) then the value of x is

If sin-1 (2a/1+a2) + cos-1(1-a2/1+a2) = tan-1(2x/1-x2),where a, x ∈ [0,1) then the value of x is (a)0

If sin-1 (2a/1+a2) + cos-1(1-a2/1+a2) = tan-1(2x/1-x2),where a, x ∈ [0,1) then the value of x is (a)0(b) a/2

If sin-1 (2a/1+a2) + cos-1(1-a2/1+a2) = tan-1(2x/1-x2),where a, x ∈ [0,1) then the value of x is (a)0(b) a/2(c) a

a(d) ,2a/1-a2

We have, sin-1 (2a/1+a2) + cos-1(1-a2/1+a2) = tan-1 2x/(1-x2)