If sin ¤ = 1/√3 find all trigonometric ratio
Answers
Answered by
0
Step-by-step explanation:
sin=1/3=P/H
By pythagoras theorem
H^2=B^2+P^2
3^2=B^2+1^2
9-1=B^2
B= 2ROOT2
COS= B/H= 2ROOT2/3
TAN= P/B= 1/2ROOT2
COSEC= H/P=3
SEC= H/B= 3/2ROOT2
COT= B/P= 2ROOT2
Subscribe my yt channel JK Tutorial 1M It is an educational channel for cbse students Maths and science videos are available here
Similar questions