Question

If sin ¤ = 1/√3 find all trigonometric ratio​

Answer 1

Step-by-step explanation:

sin=1/3=P/H

By pythagoras theorem

H^2=B^2+P^2

3^2=B^2+1^2

9-1=B^2

B= 2ROOT2

COS= B/H= 2ROOT2/3

TAN= P/B= 1/2ROOT2

COSEC= H/P=3

SEC= H/B= 3/2ROOT2

COT= B/P= 2ROOT2

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