Question

If Sin θ = 1/3 ,then Cos θ will be-​

Answer 1

Explanation:

sin A =p/h

p/h=1/3

p=1,h=3,b=?

by Pythagoras theorem

h^2=p^2+b^2

3^2=1^2+b^2

9-1=b^2

b^2=8

b=2√2

cos A=b/h

=2√2/3

Answer 2

Answer:

sinthita =1/3

sin thita =p/h

so p=1 and h=3

now base = 2√2

cos thita=b/h= 2√2/3