Question

If sin = 1/3 then cotA=​

Answer 1

Answer:

suppose,ABC is a right angled where<B=90°

given, sinA,= 1/3

= AB/AC=1/3=k(suppose)

= AB=k , AC=3k

now,from ABC right angled,

AC2=AB2+BC2

=(3k)2=k2+BC2

= 9k2=k2+BC2

= 9k2-k2=BC2

now, BC2=8k2

BC=√8k

now, cotA=BC/AB

=cotA=√8k/k

=cotA=√8