Question

If sinθ= 1/3, then find the value of 2cot^2θ +2

Answer 1

sin θ = 1/3
so cos θ = root 1- sin ka square θ = root 1 - 1/9 = 2 root 2 / 3
so cot θ = cos θ / sin θ = 2 root 2
now 2 cot [t ka square]  θ+2 = 2 multiplies by 2 root 2 ka square+2 = 16 + 2 = 18