Question

if sin =1/3 , then find the value of 2cot2 0 + 2​

Answer 1

by using Pythagoras theorm..

h^2=p^2+b^2

h^-p^2=b^2

➡here p =1 ,and h =3 is given 】

so,,b=√h^2-p^2

=>√3^2-1^2

=>√9-1

➡√8

➡2√2

>>>>>>>>>>>>>>>>>>>>>>>

now ,you know cot¢=b/p=2√2/1

so...

putting the value on question..

2cot^2^2¢+2

=>2*(2√2)^2+2

=>2*8+2

=>18 Ans..