If sinθ = 1/3 , then the value of (9 cot2θ + 9) is
(A) 1 (B) 81 (C) 9 (D) 1/81
NCERT Class X
Mathematics - Exemplar Problems
Chapter _QUESTION PAPER SET II
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9cot²Ф+9=9(cot²Ф+1)=9(cosec²Ф)=9×1/sin²Ф=9×9=81
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