If sinθ= 1,then find the value of (2cot2 θ+2) 3
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0
here I've assumed theta as alpha

2(0)2+3
=3
2(0)2+3
=3
Answered by
0
Hope it helps..
Best of luck Buddy:))
Best of luck Buddy:))
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The ques was ro find
(2cot^2+2)3
not
(2cot^2)3...
hope u understand and beware:))