if sin 10 theta is equal to cos 8 theta and 10 theta is a positive acute angle let us find the value of tan
9 thet
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Step-by-step explanation:
sin 10 theta = cos 8 theta
cos (90°- 10 theta)=cos 8 theta
90°-10 theta =8 theta
90° = 10 theta + 8 theta
90°=18 theta
theta = 90°/18
theta = 5°
Now,
tan 9 theta = tan 9×5
tan 45°= 1
ans: 1
Answered by
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The value of tan 9θ = 1.
Given :
sin 10 θ = cos 8 θ and 10 θ is acute
To find :
The value of tan 9θ.
Solution:
Given that sin 10 θ = cos 8 θ and 10 θ is acute.
sin 10 θ = sin (90 - 8θ)
10θ = 90 - 8θ
10θ + 8θ = 90
18θ = 90
θ = 90/18
θ = 5
9θ = 9 * 5 = 45.
Therefore,
tan 9θ = tan 45
tan 9θ = 1
Hence , the value of tan 9θ = 1.
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