If sin =
11/61
find cos theta, tan theta.
Answers
Answered by
2
Answer:
cosθ = 60/61
tanθ = 11/60
Step-by-step explanation:
General relation between sin and cos is
sin^2 θ + cos^2 θ = 1 ...(1)
Given sinθ = 11/61
Substitute in (1)
we get
(11/61)^2 + cos^2 θ = 1
cos^2 θ = 1 - 121/3721
cos^2 θ = 3600/3721
Take square root on both sides then we get
cosθ = 60/61
Therefore cosθ = 60/61
tanθ = sinθ / cosθ
Therefore tanθ = 11/60
Answered by
4
sin¢=11/61=perpendicular/hypotenuse
so base =√(61)^2-(11)^2 =60
so we know that cos ¢=base /hypotenuse
so we get cos¢=60/61
hope it's helpful to you....
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