Math, asked by 8956666060, 2 months ago

If sin =
11/61
find cos theta, tan theta.​

Answers

Answered by Anonymous
2

Answer:

cosθ = 60/61

tanθ = 11/60

Step-by-step explanation:

General relation between sin and cos is

sin^2 θ + cos^2 θ = 1  ...(1)

Given sinθ = 11/61

Substitute in (1)

we get

(11/61)^2 + cos^2 θ = 1

cos^2 θ = 1 - 121/3721

cos^2 θ = 3600/3721

Take square root on both sides then we get

cosθ = 60/61

Therefore cosθ = 60/61

tanθ = sinθ / cosθ

Therefore tanθ = 11/60

Answered by Itzmarzi
4

sin¢=11/61=perpendicular/hypotenuse

so base =√(61)^2-(11)^2 =60

so we know that cos ¢=base /hypotenuse

so we get cos¢=60/61

hope it's helpful to you....

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