Question

If sin????=12/13 , find the value of sin²????-cos²????/2sin????cos????*1/tan²????

Answer 1

Step-by-step explanation:

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Answer 2

sin²θ-cos²θ/2sinθcosθ * 1/ tan²θ = 0.172

Step-by-step explanation:

Given: sinθ = 12/13

To find: value of sin²θ-cos²θ/2sinθcosθ * 1/ tan²θ

Solution:  

  sinθ = 12/13 = Opposite / Hypotenuse.

So Adjacent = √(13² - 12² = √(169 - 144) = √25 = 5

 Now sinθ = 12/13

Cosθ = 5/13

Tanθ = 12/5

sin²θ-cos²θ/2sinθcosθ * 1/ tan²θ = [(12/13)² - (5/13)²] / 2.(12/13)(5/13)  * 1/(12/5)²

 = (144-25/169) / (24*5/169) * 25/144

 = 119/ 120 *25/144

= 0.172

sin²θ-cos²θ/2sinθcosθ * 1/ tan²θ = 0.172