If sin 19° = a, find the value of cos 71°, tan 71° sec 19° in terms of a.
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Answer:
cos71=sin(90-71)=sin19=a
and dude pls check the question becoz in the 2nd one I think it would be tan71/cos19
Then the ans of the 2nd one would be 1/sin19=1/a
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Step-by-step explanation:
cos71=sin(90-71)=sin19=a
and dude pls check the question becoz in the 2nd one I think it would be tan71/cos19
Then the ans of the 2nd one would be 1/sin19=1/a
Please mark It As Brainliest
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