If sin 2{ (2/1) • (3/2) • (4/3) ••••(x-1)/(x-2)} = 1, 0º < x < 100° then the value of x is equal to:
(A) 91°
(C) 49°
(B) 80°
(D) 46°
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Sin2(1/2×2/3×3/4…x-1/x-2)=1 gives
Sin2(1/x-2)=1
Because all the terms will cancel except these two terms
Since 0°<x<100°
Sin2(1/x-2)=Sin(360n+90°)
Which gives
2(1/x-2)=360n+90°
1/x-2=180n+45°
X=(1/180n+45°)+2
X=91/45°for n=0
X=451/225 for n=1
By this way there may be many possible values such as
{X:2<X</=91/40°}
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