Question

if sin ²^2 beta - cos²^ beta =2 then beta is​

Answer 1

Answer:

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Answer 2

SOLUTION

TO DETERMINE

If 2sin²β – cos²β = 2 then β is

EVALUATION

Here it is given that

2sin²β – cos²β = 2

Now

2sin²β – cos²β = 2

⇒ 2sin²β – ( 1 - sin²β ) = 2

⇒ 2sin²β - 1 + sin²β = 2

⇒ 3sin²β - 1 = 2

⇒ 3sin²β = 3

⇒ sin²β = 1

⇒ sinβ = 1

⇒ β = 90°

FINAL ANSWER

If 2sin²β – cos²β = 2 then β is 90°

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