If Sin^2 A = 2sinA then find the value of A
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your question is wrong
ektabhardwaj77798:
I have checked the question twice.. Before posting.. May be its misprinted in the book
l can say with guarantee because sin is always less than or equal to 1 but in question it is equal to 2
Okay then..
Answered by
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sin2A=2sinA
2sinA.cosA-2sinA =0
2sinA(cosA-1)=0
either 2sinA=0
sinA=0
sinA=sin0°
A= 0°
or cosA -1=0
cosA=1
cosA=cos 0°
A=0° , Answer
2sinA.cosA-2sinA =0
2sinA(cosA-1)=0
either 2sinA=0
sinA=0
sinA=sin0°
A= 0°
or cosA -1=0
cosA=1
cosA=cos 0°
A=0° , Answer
it's not sin2A there is sin squareA
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