If sin^2 A + sin^2 B = 2 , then A + B =
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Answer:
0°
Step-by-step explanation:
\begin{gathered}\sin 2B = 2\sin B \\\\\sin 2\theta = 2 \sin\theta\cos\theta\\\\2 \sin B \cos B =2 \sin B\end{gathered}
sin2B=2sinB
sin2θ=2sinθcosθ
2sinBcosB=2sinB
\cos B = \frac{2\sin B }{2\sin B}cosB=
2sinB
2sinB
\begin{gathered}\cos B =1\\\\\cos B = 0\\\\\angle B = 0^\circ\end{gathered}
cosB=1
cosB=0
∠B=0
∘
hence , The value of B is 0°
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