If sin + 2 cos = 1 prove that 2 sin - cos = 2.
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If sin∝ + 2 cos∝ = 1 prove that 2 sin ∝- cos∝ = 2.
now
sin∝ + 2 cos∝ = 1
sin∝ = 1 - 2 cos∝
sin²∝ + cos²∝ = 1
( 1 - 2 cos∝ )² + cos²∝ = 1
5cos²∝ - 4cos∝ = 0
cos∝ = 0,0.8 , sin∝ = 1, 0.6
(cos∝ , sin∝) = ( 0,1) or ( 0.8 , 0.6)
ist. case
2 sin ∝- cos∝ = 2 - 0 = 2 , correct
2nd case
2 sin ∝- cos∝ = 2*0.6 - 0.8 = 0.4 ≠ 2
only first case is o.k.
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