Question

if sin^2 Q=1/2 then find cos^2 Q​

Answer 1

Answer:

1/2

Step-by-step explanation:

Given - sin²Q = 1/2

To Find - cos²Q

sin²Q = 1/2

1-cos²Q = 1/2

cos²Q = 1-1/2 = 1/2

Answer 2

$\sin^{2} \theta = \frac{1}{2}$

$\sin \theta = \sqrt{ \frac{1}{2} }$

$\sin \theta = \sin45 ^{o}$

$\theta = 45^{o}$

Now,

${cos}^{2} \theta = \sqrt{ \frac{1}{2} }$