If sin^2 theta+cos^2 theta=1 and tan^2 theta-sec^2 theta=1
Then what is sin^2 theta + sec^2 theta
Answers
Answered by
1
sin²Q = -sec²Q
sin²Q = -(1+cot²Q)
==> -1-cot²Q
==> -1-(cos²Q/sin²Q)
==> - sin²Q-cos²Q/sin²Q
==> -(sin²Q+cos²Q/sin²Q)
==> -(1/sin²Q)
so, sin²Q = -1/sin²Q
sin²Q = -(1+cot²Q)
==> -1-cot²Q
==> -1-(cos²Q/sin²Q)
==> - sin²Q-cos²Q/sin²Q
==> -(sin²Q+cos²Q/sin²Q)
==> -(1/sin²Q)
so, sin²Q = -1/sin²Q
Similar questions