If sinθ = 20/
29
then find cosθ .
Answers
Answered by
1
Answer:
cosx=√(1-sin²x)
=√(1-(20/29)²)
cosx =14/29
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Answered by
1
Answer:
Step-by-step explanation:
cosx=√(1-sin²x)
=√(1-(20/29)²)
cosx =14/29
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