Question

if sin 2A = 4/5
find tan A
0<= A <= 45

Answer 1

Answer:

Step-by-step explanation:

As given : sin2A=45

sin2A=2tanA1+tan2A

⇒2tanA1+tan2A=45

⇒10tanA=4+4tan2A

⇒5tanA=2+2tan2A

⇒2tan2A−5tanA+2=0

⇒2tan2A−4tanA−tanA+2=0

⇒2tanA(tanA−2)−1(tanA−2)=0

⇒(2tanA−1)(tanA−2)=0

⇒tanA=12(sinceA≤π4⇒tanA≠2)

Answer 2

Answer:

Step-by-step explanation:

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