Question

if Sin 2A+B= √3/2 and cos 3A-B = 1/√2 then find A and B​

Answer 1

Answer:

Step-by-step explanation:

Sin(2A+B) = √3/2

=> Sin(2A+B) = SIn60°

=> 2A + B = 60°  -------------- (1)

Cos(3A-B) = 1/√2

=> Cos(3A-B) = Cos45°

=> 3A - B = 45°  ---------------- (2)

Solve (1) and (2) by addition

2A + B = 60

3A - B = 45

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5A = 105°

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=> A = 21°

=> B = 60 - 2*21 = 60 - 42 = 18°.