if sin 2A = sin 2B + sin 2C , prove that either B= 90 or C = 90
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sin 2A=2sin(B+C)cos(B-C)
2 sinA cosA=2sinA cos(B-C)
cosA=cos(B-C) or cos (C-B)
A=B-C or A=C-B
A+C=B or A+B=C
A+B+C=2B or A+B+C=2C
180=2B or 180=2C
B=90°or C=90°
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