Math, asked by Daizy43, 10 months ago

If sin 2theeta=k, then- tan^3theeta/1+tan^2 + cot^3theeta/1+cot^2theeta =
(a) 1-k²/k
(6) 2-k²/k
(c) k²+1 (d) 2-k²

Answers

Answered by Anonymous

1

Answer : Option (C) (2-k²)/k

I hope it will be helpful for you ☺️

Fóllòw MË ❤️

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