If sin 2theeta=k, then- tan^3theeta/1+tan^2 + cot^3theeta/1+cot^2theeta =
(a) 1-k²/k
(6) 2-k²/k
(c) k²+1 (d) 2-k²
Answers
Answered by
1
Answer : Option (C) (2-k²)/k
I hope it will be helpful for you ☺️
Fóllòw MË ❤️
Attachments:
Similar questions