If sin 2theta=cos(theta-36deg),theta and theta-26deg are acute angles,then find the value of theta.
Note:2 is not the power,it is sin 2theta.
Deg means degrees.
Answers
Answered by
22
HEY FRIEND
HERE IS YOUR ANSWER
sin2@=cos(@-36°)
[USING cosA=sin(90-A) ]
sin2@=sin(90-(@-36))
2@=90-@+36
2@+@=126
3@=126
@=126/3
@=42°
HOPE THIS HELPS YOU
HERE IS YOUR ANSWER
sin2@=cos(@-36°)
[USING cosA=sin(90-A) ]
sin2@=sin(90-(@-36))
2@=90-@+36
2@+@=126
3@=126
@=126/3
@=42°
HOPE THIS HELPS YOU
Answered by
8
Hii friend.....★★★★★
there is your answer
__________________________
Given that
sin 2ø=cos (ø-36°)
here putting
cos A=sin(90-A)
so, sin2ø=sin [90-(ø-36°)]
=》2ø=90-ø+36
=》2ø+ø=126
=》3ø=126
=》ø=42°
........♥♥♥thanks♥♥♥...
....I think it will help you then you mark me brainlist please please. .....
★★★★★★★★★★★★★★★★★★★★★★
____________________________
★★★THE END★★★
there is your answer
__________________________
Given that
sin 2ø=cos (ø-36°)
here putting
cos A=sin(90-A)
so, sin2ø=sin [90-(ø-36°)]
=》2ø=90-ø+36
=》2ø+ø=126
=》3ø=126
=》ø=42°
........♥♥♥thanks♥♥♥...
....I think it will help you then you mark me brainlist please please. .....
★★★★★★★★★★★★★★★★★★★★★★
____________________________
★★★THE END★★★
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