if sin^2x=cos^3x,then the value of (cot^6x-cot^6x) is?
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cot^6x - cot²x = cos^6x/sin^6x - cos²x/sin²x = (cos^3x)²/sin^6x - cos²x/cos³x = (sin²x)²/sin^6x - 1/cosx = 1/sin²x - 1/cos x = 1/cos³x - 1/cosx = sin²x/cos³x = sin²x/sin²x = 1
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