If sin 2x = sin30.cos60+sin60.cos30 , find value of. x
Answers
Answered by
33
sin 2x = sin60.cos30+sin30.cos60
sin2x = sin ( 60 + 30 )
sin 2x = sin 90
2x = 90
x = 45°
FORMULA USED :
sin(A+B) = sinAcosB + cosAsinB
sin2x = sin ( 60 + 30 )
sin 2x = sin 90
2x = 90
x = 45°
FORMULA USED :
sin(A+B) = sinAcosB + cosAsinB
simar21:
hlo
Answered by
9
Given Equation is sin2x = sin30 cos 60 + sin 60 cos 30.
We know that sinAcosB + sinBcosA = sin(A+B).
Then,
sin2x = sin(30 + 60)
sin2x = sin90
2x = 90
x = 90/2
x = 45.
Hope this helps!
We know that sinAcosB + sinBcosA = sin(A+B).
Then,
sin2x = sin(30 + 60)
sin2x = sin90
2x = 90
x = 90/2
x = 45.
Hope this helps!
Similar questions