Math, asked by simar21, 1 year ago

If sin 2x = sin30.cos60+sin60.cos30 , find value of. x

Answers

Answered by Danica9
33
sin 2x = sin60.cos30+sin30.cos60

sin2x = sin ( 60 + 30 )

sin 2x = sin 90

2x = 90

x = 45°

FORMULA USED :

sin(A+B) = sinAcosB + cosAsinB

simar21: hlo
simar21: how cos (60-30)
simar21: ??
simar21: sry sin (60-30)
simar21: ??
Danica9: sinAcosB + cosBsinA = sin(A-B)
Danica9: its a formula
simar21: but ans is 45
simar21: ur ans is 15
simar21: ??
Answered by siddhartharao77
9
Given Equation is sin2x = sin30 cos 60 + sin 60 cos 30.

We know that sinAcosB + sinBcosA = sin(A+B).

Then,

sin2x = sin(30 + 60)

sin2x = sin90

2x = 90

x = 90/2

x = 45.


Hope this helps!

siddhartharao77: If possible brainliest it
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