Question

if sin 3×=1 and 0°≤3×≤90°; find the value of i.) sin x, ii.) cos 2x, iii.) tan²x-sec²x. please answer me fast​

Answer 1

Sin3x = 1

3x = 90°

x = 90°/3 = 30°

Sinx = Sin30 = 1/2

Cos2x = Cos60 = 1/2

tan²x - sec²x = tan²30 - sec²30 = 3 - (2/3) = 7/3

Answer 2

Step-by-step explanation:

sin 3x=1

sin 3x=sin 90

3x=90

x=30

I)sin x=sin 90 =1

ii)cos 2x=cos 2*30=cos 60= 1/2

iii)tan^2x-sec^2x= tan^2 30°- sec^2 30°

= 1/3-4/3

= -1

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