Question

if sin=3/4 and tan=9/2 then cosx is ??

Answer 1

$\tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) }$
$\cos( \alpha ) = \frac{ \sin( \alpha ) }{ \tan( \alpha ) }$
$\cos( \alpha ) = \frac{ \frac{3}{4} }{ \frac{9}{2} }$

$\cos( \alpha ) = \frac{3 \times 2}{9 \times 4}$

$\cos( \alpha ) = \frac{1}{6}$
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