Question

If Sinθ = -3/5 , θ lies in third quadrant then find the value of Cosθ​

Answer 1

Step-by-step explanation:

$\sin( \alpha ) = \frac{ - 3}{5 } \\ \\ \alpha \: lies \: in \: third \: quadrant \\ \\ then \: \: \: \cos( \alpha ) = - \frac{ \sqrt{ {5}^{2} - {3}^{2} } }{5} = - \frac{4}{5}$

Answer 2

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