Question

if sin =3/5 show that 4 tan +3sin -6cos =0

Answer 1

hey there
sin a = 3/5
a = 37°

tan 37° - 3/4
cos 37° -4/5
4× 3/4+ 3×3/5 -6×4/5
= 0
hope it helped you please mark as brainliest

Answer 2

we know that...
sin =p/h=3/5
here p=3and h=5
then we have to find the value of b

according to pithagorus theorem

p^2+b^2=h^2
b^2=h^2-p^2
b^2=25-9=16
b=4

now ....
4tan+3sin-6cos
=4×p/b+3×p/h-6b/h
=4×3/4+3×3/5-6×4/5
=12/4+9/5-24/5
=3-15/5
=3-3
=0
.....I think it will help you. .....