Question

If sinθ=3/5 then tanθ=


​

Answer 1

$\sin = \frac{3}{5} = \frac{AB}{BC}$

By Pythagoras theorem ,,,

${AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ {5}^{2} = {3}^{2} + {BC}^{2} \\ \\ 25 - 9 = {BC}^{2} \\ \\ 16 = {BC}^{2} \\ \\ BC = \sqrt{16} \\ \\ BC = 4 = adj$

$\tan = \frac{opp}{adj} = \frac{BC}{AC} = \frac{3}{4}$

Hope it's helpful .....

Please mark it as Brainliest ..... ❤