If Sin 3θ = cos (θ– 6°), find the value of θ.
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Answered by
1
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles
SOLUTION:
GIVEN:
Sin 3θ = cos (θ– 6°)
cos (90° - 3θ ) = cos (θ– 6°)
[ cos ( 90° - θ) = sin θ ]
90° - 3θ = θ – 6°
3θ + θ = 90 °+ 6°
4θ= 96 °
θ = 96°/4
θ = 24°
Hence , the value of θ is 24°.
HOPE THIS WILL HELP YOU..
θ & (90° - θ) are complementary angles
SOLUTION:
GIVEN:
Sin 3θ = cos (θ– 6°)
cos (90° - 3θ ) = cos (θ– 6°)
[ cos ( 90° - θ) = sin θ ]
90° - 3θ = θ – 6°
3θ + θ = 90 °+ 6°
4θ= 96 °
θ = 96°/4
θ = 24°
Hence , the value of θ is 24°.
HOPE THIS WILL HELP YOU..
Answered by
0
Sin3 theeta = sin ( 90 - ( theeta - 6)
Sin3 theeta = sin ( 96 - theeta)
Sin3 theeta + sin theta = 96
sin4 theta = 96
Sin theta = 24
Sin3 theeta = sin ( 96 - theeta)
Sin3 theeta + sin theta = 96
sin4 theta = 96
Sin theta = 24
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