Math, asked by BrainlyHelper, 1 year ago

If Sin 3θ = cos (θ– 6°), find the value of θ.

Answers

Answered by nikitasingh79
1
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles

SOLUTION:

GIVEN:
Sin 3θ = cos (θ– 6°)
cos (90° - 3θ ) =  cos (θ– 6°)

[ cos ( 90° - θ) = sin θ ]

90° - 3θ = θ – 6°
3θ + θ = 90 °+ 6°
4θ= 96 °
θ = 96°/4
θ = 24°

Hence , the value of θ is 24°.

HOPE THIS WILL HELP YOU..
Answered by vinaymenon007
0
Sin3 theeta = sin ( 90 - ( theeta - 6)

Sin3 theeta = sin ( 96 - theeta)

Sin3 theeta + sin theta = 96

sin4 theta = 96


Sin theta = 24
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