Question

if sin^3 theeta and cos ^3 theeta =c then the correct answer is????????​

Answer 1

$\huge\mathfrak\blue{ƛƝƧƜЄƦ:-}$.

sin3θ=cos(θ−26°)

⇒sin3θ=sin[90°−(θ−26°)]

⇒3θ=90°−(θ−26°)

⇒4θ=116°

⇒θ=29°

Hence, the answer is 29°.

Answer 2

$\sf \: sin3θ=cos(θ−26°)$

$\longrightarrow \sf \: sin3θ=sin{90°−(θ−26°)}$

$\longrightarrow \sf3θ=90°−(θ−26°)$

$\longrightarrow \sf4θ=116°$

$\sf \longrightarrow {⇒θ= \frac{116}{4} }$

$\longrightarrow \: \sf \red{ \boxed{ \theta = 29\degree}}$