If sin 3 theta = cos ( theta - 6 ) and 3 theta and theta - 6 are acute angles, find the value of theta
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Step-by-step explanation:
sin 3Ф = cos ( Ф - 6)
sin 3Ф = sin ( 90 - Ф + 6) [we know, sin(90 - Ф) = cos Ф
3Ф = 90 + 6 - Ф
3Ф + Ф = 96
4Ф = 96
Ф = 96/4
Ф = 24
i hope this will help you
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