Question

if sin 3 theta = cos ( theta-6 degree) where 3 theta and ( theta-6 degree) both r acute angle then what is the value of theta

Answer 1

sin3@=cos(@-6°),

sin3@=sin[90°-(@-6°)],. {since cosA=sin(90°-A)},

then
3@=[90°-(@-6°),

3@=90°-@+6°,

then
3@+@=90°+6°,

4@=96°,

hence
@=96°/4=24°

Answer 2

Answer:

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