Question

if sin 30=cos (teeta-6 degree)and 30( teeta -6degree) are acute angles find the value of teeta

Answer 1

sin3∅ = cos(∅ - 6)

sin3∅ = sin[ 90 - (∅ - 6)]

sin3∅ = sin (90 - ∅ + 6)

3∅ = 90 - ∅ + 6

3∅ + ∅ = 96

4∅ = 96

∅ = 96/4

∅ = 24

I hope this will help you

(-:

Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...

Here, we're going to use the formula
sin x = cos (90-x)
$\sin(3 \alpha ) = \cos( \alpha - 6) \\ \cos( \alpha - 6) = \sin(90 - ( \alpha - 6)) = \sin(96 - \alpha ) \\ \sin(3 \alpha ) = \sin(96 - \alpha )$
Comparing...
$3 \alpha = 96 - \alpha \\ 4 \alpha = 96 \\ \alpha = 24$
Assume theta as alpha.

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