Question

if sin (30°-a)= cos (60°+b )then
(a) a - b = 30° (b) a-b=0
(c) a+b=60° (d) a - b = 60°​

Answer 1

Answer:

$\sin(30 - a) = \cos(60 + b) \\ \cos(60 + a) = \cos(60 + b) \\ 60 + a = 60 + b \\ so \\ a - b = 0 \\ ansssssssssssssssss$

Step-by-step explanation:

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