Question

If sin 30° - ½ then find

i) Cos 30° ii) Tan 30° iii) Sec 30°
iv) Cosec 30° v) cot 30°

If sin 60° - √3/2 then find

i) cos 60° ii) Tan 60° iii) Sec 60°
iv) Cosec 60° and v) Cot 60°

solve the problem.​

Answer 1

Step-by-step explanation:

the above are the answer

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Answer 2

Answer:

Sin 30 degree =1/2=P/H

So, by Pythagoras theorem, we will find out Base.

2^2=1^2+B^2

4-1=B^2

B=√3

I) Cos30 degree = √3/2=B/H

II) Tan30 degree =P/B=1/√3

III) Sec30 degree= H/B=2/√3

IV) Cosec30 degree =H/P=2/1

V) Cot30 degree =B/P=√3/1

Sin60 degree =√3/2=P/H

So, by Pythagoras theorem, we will find out base.

2^2=(√3)^2+B^2

4=3+B^2

√1=B

I) Cos60 degree=B/H=√1/2

II) Tan60 degree=P/B=√3/√1

III) Sec60 degree =H/B=2/√1

IV) Cosec60 degree =H/P=2/√3

V) Cot60 degree =B/P=√1/√3

Hope! you get your answer in well mannered way.