If sin 30° - ½ then find
i) Cos 30° ii) Tan 30° iii) Sec 30°
iv) Cosec 30° v) cot 30°
If sin 60° - √3/2 then find
i) cos 60° ii) Tan 60° iii) Sec 60°
iv) Cosec 60° and v) Cot 60°
solve the problem.
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Answer:
Sin 30 degree =1/2=P/H
So, by Pythagoras theorem, we will find out Base.
2^2=1^2+B^2
4-1=B^2
B=√3
I) Cos30 degree = √3/2=B/H
II) Tan30 degree =P/B=1/√3
III) Sec30 degree= H/B=2/√3
IV) Cosec30 degree =H/P=2/1
V) Cot30 degree =B/P=√3/1
Sin60 degree =√3/2=P/H
So, by Pythagoras theorem, we will find out base.
2^2=(√3)^2+B^2
4=3+B^2
√1=B
I) Cos60 degree=B/H=√1/2
II) Tan60 degree=P/B=√3/√1
III) Sec60 degree =H/B=2/√1
IV) Cosec60 degree =H/P=2/√3
V) Cot60 degree =B/P=√1/√3
Hope! you get your answer in well mannered way.
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