Question

If sin 32=1 find 2 ?​

Answer 1

Answer:LHS = sin 32° . cos 58° + cos 32° . sin 58°

= sin 32° . cos (90-32)° + cos 32° . sin (90-32)°

= sin 32° . sin 32° + cos 32° . cos 32°

= sin²32° + cos²32°

= 1

= RHS

Therefore, LHS = RHS

sin 32° . cos 58° + cos 32° . sin 58° = 1

Hence proved!

Formuale used :-

sin A = cos (90-A)

cos A = sin (90-A)

sin²A + cos²A = 1

Step-by-step explanation:Follow me

Answer 2

Answer:

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