Question

If sin 33° = k, then find cos 57° and tan 57 °.

user giving right answer with full process on notebook will get 20 thanks and 1 follow​

Answer 1

Refer the image

Hope it helps uhh~

Answer 2

Answer:

Cos 57° = k  

tan 57° = 1 - k^3

Step-by-step explanation:

Given :  Sin 33° = k

Sin ( 90° - 57° ) = k ,

Cos 57° = k                                              ( We know Sin ( 90° - θ ) =  Cos  θ )

We know : Sin2 θ +  Cos2 θ =  1  , So

Sin^2 57° +  Cos^2 57° =  1  ,

Sin^2 57° =  1 - Cos^2 57°  ,

Sin^2 57° =  1 - k^2 ,

Sin 57° =  1 - k^2

Then ,

Sin ( 90° - 33° ) =  1 - k^2 ,

tan θ  = Sin θCos θ , So

tan 57°  = Sin 57°Cos 57° = 1 - k^3